Thursday

April 17, 2014

April 17, 2014

Posted by **PLEASE HELP** on Friday, January 25, 2013 at 6:39pm.

- PHYSICS 2 -
**drwls**, Friday, January 25, 2013 at 7:25pmLet the smaller resistance be R1 and the larger R2.

1.99 = 12.0/(R1 + R2)

10.7 = 12/R1 + 12/R2

Solve the simultaneous equations.

R1 + R2 = 6.03

R2 = 6.03 - R1

10.7 = 12/R1 + 12/(6.03 - R1)

10.7*R1*(6.03-R1) = 12(6.03-R1) +12R1

64.51 R1 -10.7 R1^2 = 72.36

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