Friday

August 1, 2014

August 1, 2014

Posted by **Darren** on Friday, January 25, 2013 at 4:53pm.

a. infinity

b. 0

c. -1/e

d. 1/e

e. none of the above

- Calc -
**Damon**, Friday, January 25, 2013 at 5:21pmintegral e^-x dx = -e^-x

so

-e^-oo - (-e^-1)

= 0 + 1/e

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