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Homework Help: Calculus

Posted by Anonymous on Friday, January 25, 2013 at 4:40pm.

The displacement (in meters) of a particle moving in a straight line is given by s=2t^3 where is measured in seconds. Find the average velocity of the particle over the time interval [10,13].

the average velocity is 798

What is the instantaneous velocity of the particle when t=10?

• Calculus - Damon, Friday, January 25, 2013 at 5:03pm

  distance gone during seconds 10, 11, and 12 /3
  s(13) = 4394
  s(10) = 2000
  distance = 2394
  av speed = 2394/3 = 798 m/s
  
  ds/dt = v = 6 t^2
  v(10) = 6 (100) = 600 m/s
  

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