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Homework Help: Calc

Posted by Darren on Friday, January 25, 2013 at 3:56pm.

Compute the average value of f(x) = x/(x+3) over the interval [-a,a], 0 < a < 3.

a. 1 + (3/2a)ln[(3-a)/(3+a)]
b. 2a + 3ln[(3-a)/(3+a)]
c. 3/(9-a^2)
d. 1/(2a)
e. None of the above

• Calc - Steve, Friday, January 25, 2013 at 4:00pm

  x/(x+3) = 1 - 3/(x+3)
  Integral is x - 3ln(x+3)
  
  evaluate at a and -1, divide by 2a to get
  
  (a): 1 + (3/2a)ln[(3-a)/(3+a)]
  

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