• Post a New Question
• Current Questions
• Chat With Live Tutors

Homework Help: chem hwk help!

Posted by Annie on Friday, January 25, 2013 at 3:06pm.

Given the following reaction:
3 CaCl2 + 2 H3PO4 Ca3(PO4)2 + 6 HCl
How many grams of H3PO4 are needed to react completely with 1.837 g of CaCl2?

I don't understand at all

• chem hwk help! - Steve, Friday, January 25, 2013 at 3:30pm

  cmon, we just did one of these. convert grams to moles, then use the reaction to figure the relative amounts needed/produced.
  
  moles of input = 1.837/111 = .01655 moles CaCl2
  
  Each 3 CaCl2 requires 2 H3PO4
  
  so, 2/3 * .01655 = .011 moles H3PO4
  
  .011 moles H3PO4 = .011 * 98 = 1.081g
  

Answer this Question

First Name:
School Subject:
Answer:

For Further Reading