At 9:00 a.m. marsha found a parking meter that still had 5 minute until it expired. She quickly put a quarter, 1 dime, and a nickel into The meter and went to her meeting. If 5¢ buys 15 minute of parking time, at What time will The meter expire

.25 + .10 + 0.05 = $0.40

0.4 / 0.05 = 8

8 * 15 = 120 minutes

9:00 + :120 = ?

10:20

To find out at what time the parking meter will expire, we need to determine how many minutes of parking time are purchased by Marsha's coins.

First, we need to determine the value of the coins Marsha used:
- Marsha used a quarter, worth 25 cents.
- Marsha used a dime, worth 10 cents.
- Marsha used a nickel, worth 5 cents.

By adding up the values, she used a total of 25 + 10 + 5 = 40 cents.

Next, we need to find out how many minutes of parking time 40 cents buys:
- We are told that 5 cents buys 15 minutes of parking time.
- So, to find out how many minutes 40 cents buys, we can set up a proportion: 5 cents is to 15 minutes as 40 cents is to x minutes.

Using the proportion, we can solve for x:
5/15 = 40/x.

To solve for x, we cross-multiply:
5x = 15 * 40.
5x = 600.

Dividing by 5 on both sides, we find x:
x = 600/5.
x = 120.

Therefore, 40 cents buys 120 minutes of parking time.

Since Marsha had 5 minutes left on the meter when she put in the coins, we can add this to the purchased parking time:
120 minutes + 5 minutes = 125 minutes.

Finally, we need to determine the time at which the meter will expire, starting from 9:00 a.m.
If the parking meter has 125 minutes of time, which is equivalent to 2 hours and 5 minutes, we can add this to the given time:
9:00 a.m. + 2 hours and 5 minutes = 11:05 a.m.

Therefore, the parking meter will expire at 11:05 a.m.