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December 18, 2014

December 18, 2014

Posted by **Anonymous** on Friday, January 25, 2013 at 12:50pm.

- Statistic -
**MathGuru**, Friday, January 25, 2013 at 5:22pmUse the normal approximation to the binomial distribution.

mean = np

standard deviation = √npq

Therefore:

mean = .94n

standard deviation = √(n)(.94)(.06) = √(.0564n)

Using z-scores:

z = (x - mean)/sd

With the data:

1.645 = (160 - .94n)/√(.0564n)

Solve for n.

(Hint: Round answer to 165.)

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