two sides of a rectangle differ by 3.5cm.find the dimentions of the rectangles if its perimeter is 67cm?
L=W+3.5
67=2L+2W= 2(W+3.5)+2W
solve for w, then find L
nope i cant understand
will u plz explain deeper............................... i am stuck in this plz
To solve this problem, we can set up an equation using the given information.
Let's assume that the length of the rectangle is x cm and the width is y cm.
According to the problem, the difference between the two sides is 3.5 cm. So, we can write an equation as:
x - y = 3.5 --------------(1)
The formula for the perimeter of a rectangle is given by:
Perimeter = 2 * (Length + Width)
In this case, the perimeter is given as 67 cm. So, we can write another equation as:
2 * (x + y) = 67 --------------(2)
Now, we have a system of two equations (equations 1 and 2) with two variables (x and y). Let's solve this system of equations to find the dimensions of the rectangle.
From equation 1, we can rewrite it as:
x = y + 3.5
Substituting this value of x in equation 2, we get:
2 * (y + 3.5 + y) = 67
Simplifying the equation further:
2 * (2y + 3.5) = 67
4y + 7 = 67
4y = 67 - 7
4y = 60
y = 60/4
y = 15
Now, substitute the value of y back into equation 1:
x = 15 + 3.5
x = 18.5
Therefore, the dimensions of the rectangle are: Length = 18.5 cm and Width = 15 cm.