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October 25, 2014

October 25, 2014

Posted by **alejandro** on Friday, January 25, 2013 at 3:29am.

What is the probability that the adults without children are all on the committee? Express your answer to the nearest tenth of one percent.

- math30 -
**Reiny**, Friday, January 25, 2013 at 11:25amnumber of possible committees without restrictions

= C(19,7) = 50388

number of committees with the specified 4 adults

= 1 x C(15, 3) , (we must still choose 3 of the remaining 15)= 455

prob of your event = 455/50388 = 35/3876

= .0090

= appr .9%

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