Saturday

December 20, 2014

December 20, 2014

Posted by **anna** on Friday, January 25, 2013 at 1:29am.

here is exercises:

'Suppose a,b,c are integers if a|b and a|c, then a|(b+c).'

my answer:

Proof. Suppose a|b ans a|c.

By Definition of divisibility. we know a|b means there is an integer x with b= ax.

Likewise, a|c means there is an integer y for which c= ay

Thus b+c=(ax+ay)= a(x+y)

therefore a|(b+c).

- elementary math -
**Steve**, Friday, January 25, 2013 at 11:26amLooks good to me.

- elementary math -
**anna**, Friday, January 25, 2013 at 2:33pmthank you..

**Answer this Question**

**Related Questions**

college math question - Find the GCD of 24 and 49 in the integers of Q[sqrt(3...

Math: Integers - Hey guys! I need help with this problem..it tells me to write a...

discrete math - 1)prove that if x is rational and x not equal to 0, then 1/x is ...

math - Let f:ℤ+ → ℤ+ be the function defined by: for each x &#...

math help please - Let f:ℤ+ → ℤ+ be the function defined by: ...

discrete math - Let f:ℤ+ → ℤ+ be the function defined by: for...

Calculus II - 1) Compute the indefinite integral: integral 2x ln(x^2 - 8x + 18) ...

math induction - prove the product of 4 consecutive integers is always divisible...

math - Factor: x^3 - 3/4x - 1/4 The answer is: (x - 1)(x + 1/2)^2 How do I learn...

discrete math - Let A= {for all m that's an element of the integers | m=3k+7 for...