Posted by **anna** on Friday, January 25, 2013 at 1:29am.

i did use my poof to prove. im not sure im doing right.

here is exercises:

'Suppose a,b,c are integers if a|b and a|c, then a|(b+c).'

my answer:

Proof. Suppose a|b ans a|c.

By Definition of divisibility. we know a|b means there is an integer x with b= ax.

Likewise, a|c means there is an integer y for which c= ay

Thus b+c=(ax+ay)= a(x+y)

therefore a|(b+c).

- elementary math -
**Steve**, Friday, January 25, 2013 at 11:26am
Looks good to me.

- elementary math -
**anna**, Friday, January 25, 2013 at 2:33pm
thank you..

## Answer this Question

## Related Questions

- math - Factor: x^3 - 3/4x - 1/4 The answer is: (x - 1)(x + 1/2)^2 How do I learn...
- discrete math - 1)prove that if x is rational and x not equal to 0, then 1/x is ...
- discrete math - prove that if n is an integer and 3n+2 is even, then n is even ...
- *** Discrete Math *** - I would like to know if my answers are correct. I also ...
- Elementary Euclidean Geometry(Math) - Little Joseph once said: I was once asked ...
- math induction - prove the product of 4 consecutive integers is always divisible...
- discrete math - use a direct proof to show that the product of two odd numbers ...
- math - Solve each equation. What am I doing wrong because the answer is suppose ...
- Discrete Math - Theorem: For every integer n, if x and y are positive integers ...
- MS 300 - Suppose a and b are positive integers. Write a proof by contradiction ...

More Related Questions