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Posted by on Thursday, January 24, 2013 at 10:14pm.

Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius

  • phy - , Friday, January 25, 2013 at 7:39am

    KE(tr) =3kT/2= ....

    k=1.38•10⁻²³ J/K,
    T=273+27=300 K.

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