Chemistry.
posted by Brenda .
Caculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom.
A.) n=3>n=2
B.) n=4>n=3
C.) n=2>n=1
How do you do this. Could you please just show me step by step for atleaset one. Please!

1/wavelength = R*(1/n1^2  1/n2^2)
R = 1.09737E7
I tried to write n1 and square the n, not square the 1. Likewise, n2 and square the n and not the 2. The numbers are
1/n1^2 = 1/2^2 = 1/4
1/n2^2 = 1/3^2 = 1/9
wavelength in meters.
1/w =1.09737E7(1/4  1/9)
Solve for w.