Posted by **Brenda** on Thursday, January 24, 2013 at 8:44pm.

Caculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom.

A.) n=3->n=2

B.) n=4->n=3

C.) n=2->n=1

How do you do this. Could you please just show me step by step for atleaset one. Please!

- Chemistry. -
**DrBob222**, Thursday, January 24, 2013 at 10:32pm
1/wavelength = R*(1/n1^2 - 1/n2^2)

R = 1.09737E7

I tried to write n1 and square the n, not square the 1. Likewise, n2 and square the n and not the 2. The numbers are

1/n1^2 = 1/2^2 = 1/4

1/n2^2 = 1/3^2 = 1/9

wavelength in meters.

1/w =1.09737E7(1/4 - 1/9)

Solve for w.

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