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What mass of lead (II)chloride would precipitate if a solution containing 8,28 g of lead (II) ions(Pb2+) reacts with excess HCl?

  • chemistry -

    Pb^2+ + HCl ==> PbCl2 + 2H^+
    mols Pb^2+ = grams/atomic mass
    Convert mols Pb^2+ to mols PbCl2 (Use the coefficients to do this)
    Convert mols PbCl2 to grams. g = mols x molar mass.

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