___NH3+___O2->N2+H2O (this is not balanced)

how many moles of oxygen react with 0.23 moles of NH3?
HOW many moles moles of N2 will be produced when reacted with 5 mol of O2?

4NH3 + 3O2----> 2N2 +6H2O

4 mol of NH3=3 mol of O2=2 mol of N2=6 mol of H20

0.23 mol of NH3 *( 3 mol of O2/4 mol of NH3) = # of moles of O2

5 mol of O2 *( 2 mol of N2/3 mol of O2) = # of moles of N2

To answer these questions, we need to first balance the chemical equation:

NH3 + 5/2 O2 → N2 + 3 H2O

Now, we can proceed to answer the given questions:

1. How many moles of oxygen react with 0.23 moles of NH3?
We can use the balanced equation to determine the stoichiometric ratio between NH3 and O2. From the equation, we can see that for every 5 moles of NH3, 5/2 moles of O2 are required. Therefore, if 0.23 moles of NH3 are given, we can set up a proportion:

(5/2 moles O2) / (5 moles NH3) = (x moles O2) / (0.23 moles NH3)

Cross-multiplying and solving for x:

(5/2) * 0.23 = x
x ≈ 0.575 moles

Therefore, approximately 0.575 moles of O2 will react with 0.23 moles of NH3.

2. How many moles of N2 will be produced when reacted with 5 moles of O2?
Similarly, we can use the stoichiometric ratio between O2 and N2 from the balanced equation. From the equation, we can see that for every 5 moles of O2, 1 mole of N2 is produced. Therefore, if 5 moles of O2 are given, the number of moles of N2 can be determined.

Using the proportion:

(1 mole N2) / (5 moles O2) = (x moles N2) / (5 moles O2)

Cross-multiplying and solving for x:

(1/5) * 5 = x
x = 1 mole

Therefore, 1 mole of N2 will be produced when reacted with 5 moles of O2.

To determine the number of moles of oxygen that react with a certain number of moles of NH3, you need to use the balanced chemical equation.

The balanced chemical equation for the reaction is:

2 NH3 + 5/2 O2 -> N2 + 3 H2O

From this equation, you can see that for every 5/2 moles of oxygen, 2 moles of NH3 react.

1) To find out how many moles of oxygen react with 0.23 moles of NH3, you can set up the following ratio:

0.23 moles NH3 * (5/2 moles O2 / 2 moles NH3) = 0.575 moles O2

Therefore, 0.23 moles of NH3 will react with 0.575 moles of O2.

2) To determine how many moles of N2 will be produced when reacted with 5 moles of O2, you use the same balanced equation.

Using the ratio from the balanced equation:

5 moles O2 * (1 mole N2 / (5/2 moles O2)) = 2 moles N2

Therefore, when 5 moles of O2 react, 2 moles of N2 will be produced.