what volume of .025 M hydrochloric acid will neutralize 150 milliliters of .0133 M sodium hydroxide?

To calculate the volume of a solution required to neutralize another solution, you can use the following formula:

M₁V₁ = M₂V₂

Where:
M₁ is the molarity of the first solution.
V₁ is the volume of the first solution.
M₂ is the molarity of the second solution.
V₂ is the volume of the second solution.

In this case, the hydrochloric acid (HCl) is the first solution, and the sodium hydroxide (NaOH) is the second solution.

Given:
M₁ = 0.025 M (hydrochloric acid)
V₁ = ? (unknown volume of hydrochloric acid)
M₂ = 0.0133 M (sodium hydroxide)
V₂ = 150 mL (volume of sodium hydroxide)

Using the formula, we can rearrange it to solve for V₁:

V₁ = (M₂V₂) / M₁

Substituting the given values:

V₁ = (0.0133 M * 150 mL) / 0.025 M

Calculating this equation will give us the volume of hydrochloric acid needed to neutralize the given volume of sodium hydroxide.