Posted by George on Thursday, January 24, 2013 at 3:54pm.
You must be talking about this post, which Steve answered.
http://www.jiskha.com/display.cgi?id=1358971066
I would do it exactly the same way, and get the same answer.
Don't know why your prof told you it was wrong..
Here is another way to do it:
using log(A/B) = logA - logB
ln x^5 - ln x^2 = 3
ln (x^5/x^2) = 3
log x^3 = 3
3logx = 3
log x = 1
x = e^1 = e
same answer as before.
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