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February 27, 2015

February 27, 2015

Posted by **calculus** on Thursday, January 24, 2013 at 2:49pm.

Show that for any epsilon in:

|2x + 3y - 5| < epsilon

There is a delta value:

sqrt((x - 1)^2 + (y - 1)^2) < delta

Solve for delta in terms of epsilon

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I understand that this is a proof that the limit of f(x,y) as (x,y) -> (1,1) is 5.

But I'm stuck solving for delta in terms of epsilon.

thanks!

- Teddy -
**calculus**, Thursday, January 24, 2013 at 2:49pmSorry, f(x,y) = 2x+3y, not 3x+3y

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