Teddy
posted by calculus on .
f(x,y) = 3x + 3y
Show that for any epsilon in:
2x + 3y  5 < epsilon
There is a delta value:
sqrt((x  1)^2 + (y  1)^2) < delta
Solve for delta in terms of epsilon

I understand that this is a proof that the limit of f(x,y) as (x,y) > (1,1) is 5.
But I'm stuck solving for delta in terms of epsilon.
thanks!

Sorry, f(x,y) = 2x+3y, not 3x+3y