A sum of rs76.50 was pain in 50,25 and 10 paise coins. The number of 10p coin used was four times a number of 25p coin and 10 times of 50p coins how many were there of each ?????
To solve this problem, we can set up a system of equations based on the given information.
Let's assume the number of 10 paise coins is "x".
According to the problem, the number of 25 paise coins would be "4x" (four times the number of 10 paise coins).
And the number of 50 paise coins would be "10x" (ten times the number of 10 paise coins).
Now let's calculate the total value of all the coins:
Total value = (value of 10 paise coins) + (value of 25 paise coins) + (value of 50 paise coins)
The value of the 10 paise coins is 0.10 times the number of 10 paise coins: 0.10x
The value of the 25 paise coins is 0.25 times the number of 25 paise coins: 0.25 * 4x = 1.00x
The value of the 50 paise coins is 0.50 times the number of 50 paise coins: 0.50 * 10x = 5.00x
So the total value equation becomes:
76.50 = 0.10x + 1.00x + 5.00x
Simplifying the equation, we have:
76.50 = 6.10x
Now we need to solve for "x":
x = 76.50 / 6.10
x ≈ 12.54
Since we can't have fractional numbers of coins, we need to find the nearest whole numbers that satisfy the conditions. We'll round up or down to the nearest whole number.
Approximately:
x ≈ 12
Now we have the number of 10 paise coins (x = 12), the number of 25 paise coins (4x = 48), and the number of 50 paise coins (10x = 120).