An archer exerts an average force of 194 N to draw a 0.25 kg arrow back 1.2 m with the string of the bow.
How much work does the archer exert?
The "bow constant", which is the ratio of force F to pullback distance X, is
k = 194/1.2 = 161.7 N/m
The work done puling back the arrow is
W = (1/2) k X^2 = (1/2) F*X
The mass of the arrow is not needed to answer that question, but it will affect the arrow's velocity