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March 26, 2015

March 26, 2015

Posted by **frustrated** on Thursday, January 24, 2013 at 2:04am.

until it reaches equilibrium. The equilibrium length of the spring is 0.059 m.

What is the magnitude of the external electric field?

- physics -
**Elena**, Thursday, January 24, 2013 at 5:32amI believe that m= 5.1 X 10^- 3 kg

F(electr) + F(spr) = mg,

qE + k•ΔL=mg

E=( mg- k•ΔL)/q=

={5.1•10⁻³•9.8 – 2.4(0.074-0.059)}/6.6 =… V/m

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