Chem
posted by Susie .
A student measures the following data regarding the heat of fusion of ice: 25.8 g ice at 0.0°C is placed into the calorimeter which contains 100.0 g water at 21.7°C. The final temperature comes to 1.5°C. The calorimeter has a heat capacity of 15.6 J/°C.
(a) Calculate the experimental ΔHfus of ice in kJ/mol.

Let x = heat fusion ice.
(mass ice*x) + [(mass melted ice x specific heat x (TfinalTinitial)] + [mass warm water x specific heat water x (TfinalTinitial)] + Ccal(TfinalTinitial) = 0
Solve for x.
Post your work if you get stuck.