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November 1, 2014

November 1, 2014

Posted by **VD** on Wednesday, January 23, 2013 at 9:45pm.

- Trig -
**Reiny**, Wednesday, January 23, 2013 at 10:18pmYou have the pattern of "difference of squares"

(csc(B)+cot (B))(csc(B)-cot(B))

= csc^2 B - cot^2 B

But csc^ B = 1 + cot^2B , one of the identies from

sin^2 B + cos^2 B= 1

so csc^2 B - cot^2 B

= 1 + cot^2 B - cot^2 B = 1

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