Posted by Thank You on .
A plane is flying in the horizontal plane. At time t1= 0 s with the components of its velocity are vx= 100 m/s and vy= 120 m/s. At time t2= 20 s the components are vx= 80 m/s and vy = 142 m/s.
a. What was the change in the direction of the velocity?
b. What is the change in the magnitude of the plane’s velocity during this time?
c. What are the components of the average acceleration for this interval?
d. What are the magnitude and direction of the average acceleration for this interval?

Physics 
Henry,
a. tanA1 = Vy/Vx = 120/100 = 1.20.
A1 = 50.2o = Direction.
Magnitude = Vx/cosA1=100/cos50.2 =156.2
m/s.
tanA2 = 142/80 = 1.775.
A2 = 60.6o = Direction.
Magnitude = 80/cos60.6 = 163 m/s.
60.6  50.2 = 10.4o = The change in
direction.
b. 163  156 = 7 m/s.
c. a(x) = (80100)/20 = 1.0 m/s^2.
a(y) = (142120)/20 = 1.1 m/s^2.
d, tanAr = 1.1/1 = 1.10.
Ar = 47.7o = Reference angle.
A = 180 + (47.7) = 132.3o=Direction.
Mag, = 1.0/cos132.3 = 1.49 m/s^2.