A 50.0 g silver object is added to 75.5 mL of water contained in a graduated cylinder. The density of silver is 10.5 g/mL. What is the total volume in the graduated cylinder?
mass of silver/density of silver = volume of silver
volume of silver + volume of water = total volume
The density of pure silver is 10.5 g cm at 20 °C. If 5.25 g of pure silver is added to a graduated cylinder containing 11.2 mL of water, to what volume level will the water in the cylinder rises? -3 2.
To find the total volume in the graduated cylinder after adding the silver object, we need to consider the volume of the water and the volume of the silver object separately.
First, let's find the volume of the silver object. We have the mass of the silver object (50.0 g) and the density of silver (10.5 g/mL). The volume (V) of an object can be calculated using the formula:
V = mass / density
Substituting the values, we have:
V = 50.0 g / 10.5 g/mL
V ≈ 4.76 mL
So, the silver object has a volume of approximately 4.76 mL.
Next, let's consider the volume of the water in the graduated cylinder. We are given that there is 75.5 mL of water already present.
To find the total volume, we add the volume of the silver object to the volume of the water:
Total volume = Volume of water + Volume of silver object
Total volume = 75.5 mL + 4.76 mL
Total volume ≈ 80.26 mL
Therefore, the total volume in the graduated cylinder after adding the silver object is approximately 80.26 mL.