Posted by Julie on Wednesday, January 23, 2013 at 4:17pm.
just a lot of experience, some guesses, and some luck. You know from looking at it that the factors will be of the form
(5x+a)(x+b)
where the two a,b are one each of 1,9.
You need 5b+9a = 8
Now, even a cursory look assures you that there are no such a,b both positive where this can be the case.
A quick check of the discriminant shows that it is 8^2-4*9*5 = 64-180 < 0, so there are no real roots. That means no factors over the rationals.
Is there a typo here? The beast can certainly not be factored.
Related Questions
FACTORING - I can't figure out how to factor this. I know you use the ...
math - What factoring technique would be used to factor 2x^2+5x+3?
math - Can someone please help me with this factoring? Thanks! Factor 3x^2-7xy+...
algbra - i was wondering what did i do wrong in this 10. Divide (3x 2)(x...
factoring - how to factor x^4 - 2x^3 - 8x + 16 Thanks. you can factor by ...
Business Calculus - I need help with: r(x)= 4/5x^2 + 8x + 15 What do you do with...
Math (factoring) - Can someone check my answer? 5x^3 - 40 =5(x^3-8) =5(x-2)(x^2+...
math-factoring - how do you factor this 8x^3+27
Algebra - Can someone help me with this please. Andrew factored the expression ...
math- factoring - factor completely 1) 8x^3 + 27y^3 2) u^3 + 125v^3
For Further Reading