Posted by George on .
lnx^5  lnx^2 = 3 solve for the unknowns as a list.
I tried using my calculator but apparently my answer is opposite ends of the universe

Logarithms 
Steve,
since log x^n = n log x, we have
5lnx  2lnx = 3
3lnx = 3
lnx = 1
x = e
don't know what list you might be involving