Posted by tuhituhi on Wednesday, January 23, 2013 at 11:26am.
lose the CAPS LOCK, ok?
If, as I suspect, you meant
(x^6-7x^3-8) / (x+1)(x^2+2x+4)
note that x^6-7x^3-8 = (x^3-8)(x^3+1)
Now factor those two differences of cubes, ad you have
(x-2)(x^2+2x+4)(x+1)(x^2-x+1) / (x+1)(x^2+4)
= (x-2)(x^2-x+1)
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