posted by tuhituhi on .
DIVIDE X^6 -7^3 -8 BY THE PRODUCT OF X+1 AND ( X^2 +4) ?????
lose the CAPS LOCK, ok?
If, as I suspect, you meant
(x^6-7x^3-8) / (x+1)(x^2+2x+4)
note that x^6-7x^3-8 = (x^3-8)(x^3+1)
Now factor those two differences of cubes, ad you have
(x-2)(x^2+2x+4)(x+1)(x^2-x+1) / (x+1)(x^2+4)