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December 22, 2014

December 22, 2014

Posted by **tuhituhi** on Wednesday, January 23, 2013 at 11:26am.

- maths -
**Steve**, Wednesday, January 23, 2013 at 12:16pmlose the CAPS LOCK, ok?

If, as I suspect, you meant

(x^6-7x^3-8) / (x+1)(x^2+2x+4)

note that x^6-7x^3-8 = (x^3-8)(x^3+1)

Now factor those two differences of cubes, ad you have

(x-2)(x^2+2x+4)(x+1)(x^2-x+1) / (x+1)(x^2+4)

= (x-2)(x^2-x+1)

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