Posted by Maria on Wednesday, January 23, 2013 at 11:16am.
You can treat the spheres as point charges at R >2m separation. If e is the charge on each sphere, for the electrical repulsion to equal the gravitational attraction,
G M^2 /R^2 = k Q^2/R^2
GM^2 = k Q^2
G is the Newton gravity constant and k is the Coulomb law constant
Solve for Q. The number of electrons is Q/e.
e is the elctron charge.
Related Questions
Physics - Two iron spheres each have a volume of 10 cm^3 and a mass of 78g. How ...
math - A fish tank is 50 cm long, 34 cm wide and 24 cm high. It contains water ...
Physics... Coulomb's law - Two small silver spheres with a mass of 10.0g, ...
physics - how many excess electrons must be placed on each of two small metal ...
physics - Two 4.0-g spheres are suspended by 9.0-cm-long light strings (see the...
PHYSICS HELP - a cube of wood with a density of 0.78g/cm^3 is 10cm on a side. ...
chemistry - I have two problems that I'm stumped on. I know the correct ...
physics - The final charge on each of the three separated spheres in part (c) is...
Physics - Three uniform spheres are located at the corners of an equilateral ...
physics - Three uniform spheres are located at the corners of an equilateral ...
For Further Reading
