Wednesday

July 23, 2014

July 23, 2014

Posted by **chacho** on Wednesday, January 23, 2013 at 10:40am.

- Math -
**Steve**, Wednesday, January 23, 2013 at 12:07pmtaking log

_{10}of both sides,

(5-logx^3) logx = log100

(5 - 3logx)logx = 2

for ease of reading let u = logx, so we have

(5-3u)u = 2

3u^2 - 5u + 2 = 0

(3u-2)(u-1) = 0

u = 1 or 2/3

so, x = 10^1 = 10, or

x = 10^2/3 = ∛100

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