1. Identify the percent composition of sodium carbonate.
2. Determine the percent composition of calcium in calcium carbonate.
Pls. help me... my prob is that there is something in the solution that bothers me.. pls.kindly show me how to do.. i'll thank u later... :)
In your first question, 1 mole of sodium carbonate=2 moles of sodium=1 mole of carbon =3 moles oxygen. Take the moles for each of the components in sodium carbonate and multiply them by their respective molecular weights e.g. 3 moles of oxygen* 15.999g/mole to calculate the weight of oxygen in sodium carbonate. Since the molecular weight of sodium carbonate is 105.9784 g/mol, the weight that you calculate for oxygen divided by the the molecular weight of sodium carbonate multiplied by 100 will give you the percent composition of oxygen in sodium carbonate ([weight of oxygen/105.9784] *100); perform these steps for each of the additional components in sodium carbonate.
The answer to the second question is the same, but you only need to do the steps mentioned above with Ca. 1 mole of Ca= 1 mole of calcium carbonate. Take the molecular weight of Ca and divide it by the molecular weight of calcium carbonate, which is 100.0869 g/mol. Remember to multiply that number by 100 to get percent.
Why not tell us what the problem is and let us answer that specific question instead of working on problems that may or may not be troubling you.
Sure! I can help you with that.
To find the percent composition of a compound, we need to determine the mass of each element in the compound and then calculate the percentage of each element in relation to the total mass of the compound.
Let's start with the first question: the percent composition of sodium carbonate (Na2CO3).
1. First, we need to determine the molar mass of sodium carbonate by adding up the molar masses of each element in the compound.
The atomic mass of sodium (Na) is 22.99 g/mol, the atomic mass of carbon (C) is 12.01 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol.
The formula for sodium carbonate (Na2CO3) tells us that we have two sodium atoms, one carbon atom, and three oxygen atoms.
So, the molar mass of sodium carbonate is:
(2 * 22.99 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol) = 105.99 g/mol
2. Next, we need to determine the mass of each element in the compound.
The mass of sodium (Na) in sodium carbonate is:
(2 * 22.99 g/mol) = 45.98 g
The mass of carbon (C) in sodium carbonate is:
(1 * 12.01 g/mol) = 12.01 g
The mass of oxygen (O) in sodium carbonate is:
(3 * 16.00 g/mol) = 48.00 g
3. Finally, we can calculate the percent composition of each element in sodium carbonate.
The percent composition of sodium (Na) in sodium carbonate is:
(45.98 g / 105.99 g) * 100% = 43.32%
The percent composition of carbon (C) in sodium carbonate is:
(12.01 g / 105.99 g) * 100% = 11.33%
The percent composition of oxygen (O) in sodium carbonate is:
(48.00 g / 105.99 g) * 100% = 45.35%
Now, let's move on to the second question: the percent composition of calcium in calcium carbonate (CaCO3).
We'll follow the same steps as before.
1. Calculate the molar mass of calcium carbonate (CaCO3):
(1 * 40.08 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol) = 100.09 g/mol
2. Determine the mass of each element in the compound.
The mass of calcium (Ca) in calcium carbonate is:
(1 * 40.08 g/mol) = 40.08 g
The mass of carbon (C) in calcium carbonate is:
(1 * 12.01 g/mol) = 12.01 g
The mass of oxygen (O) in calcium carbonate is:
(3 * 16.00 g/mol) = 48.00 g
3. Calculate the percent composition of each element in calcium carbonate.
The percent composition of calcium (Ca) in calcium carbonate is:
(40.08 g / 100.09 g) * 100% = 40.06%
The percent composition of carbon (C) in calcium carbonate is:
(12.01 g / 100.09 g) * 100% = 11.99%
The percent composition of oxygen (O) in calcium carbonate is:
(48.00 g / 100.09 g) * 100% = 47.95%
I hope this explanation helps you understand how to find the percent composition of a compound. If you have any additional questions, feel free to ask!