A plane leaves Boston at 10 am (Boston time) and flies non-stop to LA, 2700 miles away, at 580 miles per hour (mph). On the same route, a second plane is flying non-stop from LA to Boston at 620 mph. If the second plane lease LA at 10 am (LA time), how many miles from LA will the second plane be when the two planes meet?

the two planes cover 580+620=1200 miles per hour.

So, they travel for 2700/1200 = 2.25 hrs before meeting. (why?)

In that time, the 2nd plane has traveled 2.25*620 = 1395 miles, so it is 1305 miles from LA.

To find out how many miles from LA the second plane will be when the two planes meet, we need to calculate the time it takes for the two planes to meet.

Let's start by finding the time it takes for the first plane to reach LA. The distance between Boston and LA is 2700 miles, and the first plane is flying at a speed of 580 mph.

Time = Distance / Speed
Time = 2700 miles / 580 mph

Now, let's calculate this:
Time = 4.655 hours

Since both planes leave at 10 am, and the first plane takes 4.655 hours to reach LA, we can add this time to 10 am (LA time) to determine when the two planes will meet.

Meet Up Time = 10 am (LA time) + 4.655 hours

Now, let's calculate this:
Meet Up Time = 2:39 pm (LA time)

Since the second plane leaves LA at 10 am (LA time), and they will meet at 2:39 pm (LA time), we need to determine how many hours the second plane has been flying.

Flying Time of the Second Plane = Meet Up Time - 10 am (LA time)

Now, let's calculate this:
Flying Time of the Second Plane = 2:39 pm - 10 am
Flying Time of the Second Plane = 4.65 hours

Finally, let's calculate how far the second plane will be from LA when they meet:
Distance from LA = Speed x Time
Distance from LA = 620 mph x 4.65 hours

Now, let's calculate this:
Distance from LA = 2883 miles

Therefore, the second plane will be approximately 2883 miles from LA when the two planes meet.