Saturday
December 20, 2014

Homework Help: Pre-Calculus

Posted by Caroline on Tuesday, January 22, 2013 at 10:29pm.

Solve by using the substitution method

1.x=-3y+4 and 3x+9y=12

3(-3y+4)+9y=12

-9y+12+9y12

0=0

x=-3(0)+4

x=4

Would there be infinite solutions or would it be (0,4)?

2. x=3y-1 and 2x-6y=-2

2x-6y=-2

2(3y-1)-6y=-2

6y-2-6y=-2

0=0

x=3y-1

x=3(0)-1

x=-1

Would there be infinite solutions or would it be (-1,0)?

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