Sunday
March 26, 2017

Post a New Question

Posted by on .

A 46.6 kg crate is at rest on a level floor, and te coefficient of kinetic friction is 0.32. The acceleration of gravity is 9.8M/s^2. If the crate is pushed horizontally with a force of 201.67 N, how far does it move in 3.42s? Answer in units of m

  • Physics - ,

    First calculate the friction force, Ff.
    Ff = (0.32)*M*g = 146.14 Newtons

    Then calculate the net horizontal force on the box
    Fnet = 211.67 - 146.14 = 65.53 N

    Then calculate the acceleration
    a = Fnet/M = 1.41 m/s^2

    Then use
    Distance moved = (1/2) a t^2
    (for a starting velocity of zero)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question