Posted by Mariah on Tuesday, January 22, 2013 at 4:26pm.
mols H2 @ equil = 0.627g/2 = 0.3135
M H2 @ equil = 0.3135/2L = 0.1567M
M H2 begin = (1.441/4) = 0.360M
M Br2 begin = (70.24/159.8) = 0.440M
........H2 + Br2 ==> 2HBr
I.....0.36..0.44.....0
C.....-x.....-x.......2x
E...0.36-x..0.44-x...2x
At equil (H2) = 0.157M; therefore, we know
0.36-x = 0.157 and we solve for x. Use that to calculate each of the equilibrium values, substitute those into the Kc expression and calculate Kc.
Be sure and check (confirm) those numbers. I just ran them one time on my calculator.
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