how do u do 9x^2-30xy+2y^2 ?
what do you mean by "do"? factor?
you can use the quadratic formula to get
x = (30±√(900+72y^2))/18
= (5±√(25+2y^2))/3
no simplify sorry forgot to specify..
I don't see any way to simplify it.
It doesn't factor with integers, there are no common terms. I suppose by specifying as rotation matrix, it could be rewritten as a standard hyperbola on rotated axes, or intersecting lines, but I doubt that's what you had in mind.
I don't see much to do with it.
To simplify the expression 9x^2 - 30xy + 2y^2, you can follow these steps:
Step 1: Determine if it can be factored
Check if there are any common factors between the coefficients of the terms. In this case, there are no common factors among the coefficients (9, -30, and 2).
Step 2: Identify the type of factorization
Look at the signs of the coefficients. If the middle term (-30xy) is negative, it implies that the factors will have opposite signs (one positive and one negative).
Step 3: Apply the formula for factorization
To factorize a quadratic trinomial of the form ax^2 + bx + c, you can use the formula:
(x - m)(x - n), where:
- m and n are the factors of the constant term (c), and
- m + n is equal to the coefficient of the middle term (b).
For our expression, 9x^2 - 30xy + 2y^2, we will find the factors of 2y^2.
Step 4: Find the factors
The factors of 2y^2 are (1y, 2y) and (2y, 1y).
Step 5: Determine the signs of the factors
Since the middle term is -30xy, we need to choose one positive and one negative factor.
One possible combination is:
(1y - 2y)(2y - 1y)
Step 6: Simplify
Simplifying (1y - 2y)(2y - 1y) gives us:
-y(2y - 1y) = -y(2y - y) = -y(2y^2 - y^2) = -y(2y^2 - y^2)
So, the simplified form of the expression 9x^2 - 30xy + 2y^2 is -y(2y^2 - y^2).