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December 18, 2014

December 18, 2014

Posted by **Kelsey** on Tuesday, January 22, 2013 at 3:08pm.

Write a system of equations to represent this situation. Solve the system of equations. How many student tickets sold? How many non students?

- Algebra 2 -
**Steve**, Tuesday, January 22, 2013 at 3:10pm3s+5n = 1790

s = 2n-100

(s,n) = (190,280)

- Algebra 2 -
**loliza**, Monday, February 4, 2013 at 10:28pm5n + 3n = 1790

n= tickets sold for non student

2n-100 = tickets sold for student

So,

5n + 3(2n-100)= 1790

5n + 6n - 300 = 1790

11n = 1790+300

11n= 2090

n= 190

So, substituting the value of n we 5(190)+ 3(2(190)-100) =1790

950 + 840 =1790

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