Posted by John on Monday, January 21, 2013 at 10:45pm.
kq₁/x²=kq₂/(6-x)²
2/x²=6/(6-x)²
36-12x+x²=3x²
2x²+12x-36=0
x²+6x-18=0
x = - 3ħsqrt(9+18) =
= - 3 ħ 5.2
If q₁ >0 and q₂>0 x= 2.2 cm (to the right from the left charge (between the charges))
If q₁ <0 and q₂>0 x=-8.2 cm (to the left from the left (negative) charge)
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