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A ball thrown horizontally at 22.76 m/s travels a horizontal distance of 46.81 m before hitting the ground. From what height was the ball thrown?
The time that it takes the ball to travel in the x-direction is the same amount of time that the ball takes to travel in the y-direction. Since you know the velocity of the ball and the distance, use D=V*T and solve for time (T). Once you solve for t, use t and plug it into one of the kinematic equations D=ViT+1/2(aT^2). Since in the Y-direction the initial velocity is 0 and acceleration is equal to gravity (9.8m/s^2), the equation should be give you D=1/2(9.8m/s^2)(T)^2. Solving for D gives you the height.