Posted by Ashley on Monday, January 21, 2013 at 8:23pm.
Not sure, but if since pressure in volume are inversely related you should see an increase in the pressure. so if volume decreased by 7/8, the pressure should increase by 7/8.
You don't list a pressure initially; the final pressure will be eight times (8x) the initial pressure.
Just a question, how do you get 8x the initial pressure when it decreased by 7/8?
p1 = some convenient number, say 2 atm.
v1 = 930 cc
p2 = ?
v2 = 930*1/8 = 116.25 cc.
p1v1 = p2v2
2*930 = p2*116.25
p2 = 2*930/116.25 = 16
16 is 8*2; p increased by a factor of 8.
If the volume is reduced to 1/2 its original volume the pressure must have been doubled.
If the volume is reduced to 1/3 its original volume the pressure must have been tripled.
If the volume is reduced to 1/10 its original volume the pressure must have been increased by 10 times (a factor of 10).
If the volume is decreased to 1/8 its original volume the pressure must have been increased by a factor of 8.
Got it. Should have just done the math.
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