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April 20, 2014

April 20, 2014

Posted by **Mary** on Monday, January 21, 2013 at 6:37pm.

a. the max speed

b. the max acceleration of the object. Fine the velocity of the object at t=5s

- Physics -
**Damon**, Monday, January 21, 2013 at 6:53pm10 cm = 0.1 m

x = .1 cos 2 pi t/T

v = -(2 pi/T) .1 sin 2 pi t/T

a = - (2 pi/T)^2 .1 cos 2 pi t/T = -(2 pi/T)^2 x

F = - k x

F = m a = - 2 (2 pi/T)^2 x

k= 8 pi^2/T^2 = 75

T ^2 = 8 pi^2/75

T = 1.03 s

2pi /T = 6.12

(2 pi/T)^2 = 37.5

so

if v = -(2 pi/T) .1 sin 2 pi t/T

then v max = (2 pi/T) .1

=.612

and

if a = - (2 pi/T)^2 .1 cos 2 pi t/T

then a max = .1(2 pi/T)^2

=3.75

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