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August 30, 2014

August 30, 2014

Posted by **Prince** on Monday, January 21, 2013 at 5:07pm.

- Math -
**Reiny**, Monday, January 21, 2013 at 5:30pmthe perpendicalar to the chord will be 22.1 inches

and it will meet the chord at its midpoint

So you have a rightangled triangle with the radius as the hypotenuse 6.42 ft or 77.04 inches

and shorter sides 22.1 and x

Use Pythagoras to find the radius

x^2 + 22.1^2 = 77.04^2

-use basic trig to find the central angle of the sector

-use a ration to find the area of the sector

-find the area of the triangle formed by the chord and the centre of the circle, you know the angle

Area of whole circle = 70.04^2 π

subtract the area of the triangle from the area of the sector to find the area of the segment.

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