Friday

April 18, 2014

April 18, 2014

Posted by **Lindsey** on Monday, January 21, 2013 at 4:00pm.

during the time in which his toe is in contact with the ball (about 0.247 s). If the football

has a mass of 484 g, what average force does the punter exert on the ball?

- Physics -
**Anonymous**, Monday, January 21, 2013 at 4:21pmImpulse momentum equation. From Newtons second law, F=MA. Since acceleration (A) is Change in velocity/time, the equation turns into F=M[(Vf-Vi)]/t. Multiplying both sides of the equation by t gives you Ft=M(Vf-Vi). Since initial velocity is 0, the equation turns into Ft=MVf. Rearranging the equation, to solve for F turns the equation into F=MVf/t, plug in your values for t, Vf, and M, resulting in a rearranged formula looking like F= [(0.484Kg)(9.1m/s)]/(0.247s). Solve for F. Note that I converted g to Kg first before solving.

**Related Questions**

Physics - A football punter accelerates a football from rest to a speed of 9.1 m...

Physics - A football punter accelerates a football from rest to a speed of 9.1 m...

physics - A football punter accelerates a football from rest to a speed of 9 m/s...

physics - a football punter accelerates a football from rest to a speed of 7 m/s...

physics - A football punter accelerates a football from rest to a speed of 8 m/s...

physics - A football punter accelerates a football from rest to a speed of 10 m/...

physics - A football punter accelerates a football from rest to a speed of 10 m/...

college physics - A football punter accelerates a football from rest to a speed ...

physics - A football punter accelerates a 0.35 kg football from rest to a speed ...

physics - A football punter accelerates a 0.35 kg football from rest to a speed ...