The Formula s= sqrt 30fd can be estimated the speed of s, in miles per hour that a car is traveling when it goes into a skid, where f is the coefficient of friction and d is the length of the skid marks in feet. Kody skids to a stop on a street with a speed limit of 35 mi/h. his skid marks measure 52ft and the coefficient of friction is 0.7 Kody says he was driving only 30 mi/h Kody wants to prove he wasn't speeding.
Solve the equation for d in terms of s.
Please help me ive been stuck on this for hours.
So his equation is
s = √(30(.7d))
so his speed according to your formula was
s = √((30)(.7)(52)) = 10.3 m/h
I think your formula is wrong.
A total of 71 ft of dark skid marks after collision of 2 vehicles. How fast would the vehicle that hit unit 2 be going?
t7u
The equation s = can be used to find a car’s speed s in miles per hour given the length d in feet of a skid mark and the friction factor f of the road. Police measured a skid mark of 90 feet on a dry concrete road. If the speed limit is 35 mph, was the car speeding? Explain.
10. The equation s = square root 30fd can be used to find a car’s speed s in miles per hour given the length d in feet of a skid mark and the friction factor f of the road. Police measured a skid mark of 90 feet on a dry concrete road. If the speed limit is 35 mph, was the car speeding? Explain.
To solve the equation s = √(30fd) for d in terms of s, we need to isolate the variable d.
Let's start by squaring both sides of the equation:
s^2 = 30fd
Next, divide both sides of the equation by 30f:
s^2 / (30f) = d
Therefore, the equation for d in terms of s is:
d = s^2 / (30f)
Now, let's apply this formula to the specific scenario you provided.
Kody claims he was driving 30 mi/h (s = 30 mi/h), and the skid marks measure 52 ft (d = 52 ft). The coefficient of friction is given as 0.7 (f = 0.7).
Plugging these values into the formula, we have:
d = s^2 / (30f)
d = (30 mi/h)^2 / (30 * 0.7)
d = 900 / 21 ≈ 42.86 ft
Therefore, according to the formula, the expected length of the skid marks when driving at 30 mi/h with a coefficient of friction of 0.7 is approximately 42.86 ft.
If Kody's skid marks measure 52 ft, it suggests that he was indeed driving faster than 30 mi/h, as the skid marks exceed the expected length.