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February 1, 2015

February 1, 2015

Posted by **Em** on Monday, January 21, 2013 at 2:20pm.

y = (64 − x^2)^(1/4), y = 0, x = 6, x = 7; about the x-axis

- Math -
**Steve**, Monday, January 21, 2013 at 3:36pmv = ∫[6,7] πr^2 dx

where r = y = ∜(64-x^2)

v = π∫[6,7] √(64-x^2) dx

= π(1/2 √(64-x^2) + 32 arcsin(x/8)) [6,7]

= π(√15/2 - √7 + 32(arcsin(7/8)-arcsin(3/4)))

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