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September 1, 2014

September 1, 2014

Posted by **Em** on Monday, January 21, 2013 at 2:11pm.

The base of S is a circular disk with radius 4r. Parallel cross-sections perpendicular to the base are squares.

- Math -
**Steve**, Monday, January 21, 2013 at 3:29pmusing symmetry,

v = 4∫[0,4r]∫[0,√(16r^2-x^2)] 4xy dy dx

= 512r^4

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