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April 1, 2015

April 1, 2015

Posted by **Em** on Monday, January 21, 2013 at 2:01pm.

y = −x^2 + 14x − 45, y = 0; about the x-axis

- Math -
**Steve**, Monday, January 21, 2013 at 3:20pmthe curve intersects y=0 at x=5,9

v = ∫[5,9] π (−x^2 + 14x − 45)^2 dx

= π (x^5/5 - 7x^4 + 286/3 x^3 - 630x^2 + 2025x [5,9]

= 512/15 π

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