please walk me through this I am having a hard time with this
A survey of 500 showed the following
15 had only camping
20 had only hiking trails
35 had only picnicking
185 had camping
140 had camping and hiking trails
125 had camping and picnicking
210 had hiking trails
Determine the
a) number of parks that had at least one of the features
b) had all three features
If we label the pats of the circles in our Venn diagram,
15+CH+CP+CHP = 185
CH+CHP = 140
CP+CHP = 125
20+CH+CHP+HP = 210
from these we can see that
CH = 45
CP = 30
HP = 50
CHP = 95
a) sum of them all is 290
b) CHP = 95
Sure, I can help you with that!
To determine the number of parks that had at least one of the features, we need to add up the number of parks in each category: camping, hiking trails, and picnicking. Let's break it down step by step:
a) Number of parks that had at least one of the features:
1. Start by adding up the number of parks in each category separately:
- Parks with camping only: 15
- Parks with hiking trails only: 20
- Parks with picnicking only: 35
- Parks with camping and hiking trails: 140
- Parks with camping and picnicking: 125
- Parks with hiking trails only: 210
2. Now, add the above numbers together:
15 + 20 + 35 + 140 + 125 + 210 = 545
Therefore, the number of parks that had at least one of the features is 545.
b) Number of parks that had all three features:
To determine the number of parks that had all three features, we need to find the intersection between the categories. In this case, we need to find the number of parks that had camping, hiking trails, and picnicking.
However, we only have information about the number of parks that had camping and hiking trails, and the number of parks that had camping and picnicking. We don't have direct information about the number of parks that had all three features.
So, without more information, we cannot determine the exact number of parks that had all three features.
I hope this helps you understand how to approach the problem! If you have any further questions, feel free to ask.