Posted by **Larry** on Monday, January 21, 2013 at 10:51am.

I've been stuck on this equation for a while and I don't know if i'm missing a key part to the equation.. i just need help!

If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is the mountain?

F= g ( m1 x m2)/ radius^2

f= gravitational force

g= 6.67x10^-11

m= mass

d= radius^2

earth mass= 5.98x10^24

earth radius = 6.38x10^6

- Physics -
**Steve**, Monday, January 21, 2013 at 11:29am
You know that at sea level

GM/r^2 = 9.8

Since G and M don't change, at radius R at the mountain top,

GM/R^2 = 9.772

so, R^2/r^2 = 9.8/9.772 = 1.0028653

R = 1.0014316r

R-r = 0.0014316r = 9134m

That seems a bit high. Better check my math.

- Physics -
**drwls**, Monday, January 21, 2013 at 11:33am
The actual height of Everest is 8848 m. Your number is close, and you used the right method. The difference is probably due to the use of too few significant figures for G(or GM/r^2).

## Answer This Question

## Related Questions

- Physics - Climbing to the top of Mount Everest is hard. But, it's slightly ...
- physics - Climbing to the top of Mount Everest is hard. But, it's slightly ...
- physics.... - The universal law of gravitation describes the force of gravity ...
- physics - At the top of mount everest the density of air is 1.2kilogram/meter ...
- physics - he universal law of gravitation describes the force of gravity between...
- Grade 12 Physics - A rocket ship is moving away from the earth after having been...
- vocabulary - The story of the men who first climbed to the top of Mount Everest ...
- Physics (G and g) - Please, I need help with this problem. I would really ...
- Physics - The figure shows an Atwood machine (a wheel suspended from the ...
- 3 grade english ms sue - subject and object pronouns DIRECTION - write SP if the...

More Related Questions