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Posted by on Monday, January 21, 2013 at 9:53am.

This problem is 1st order for half life.

How long would it take for the concentration of cyclopropane to decrease to 50% of its initial value? to 25% of its initial value?

Rate constant is 9.2/s

I set up like this...

t1/2= 0.693/9.2/s= 0.075s at 50%

I can't figure out how to get the answer of 0.151s from 25%...

  • Chemistry - , Monday, January 21, 2013 at 11:19am

    if it reduces to 1/2 in .075s, it will reduce to 1/4 in twice that, or .151s.

    The half-life is 0.075s, so since 1/4 = 2(1/2), it takes 2 half-lives to fall to 25%.

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