Posted by Matt on Monday, January 21, 2013 at 8:32am.
Wow, a "dragster bus"
v = at + c , a is the acceleration, v is the velocity and c is a constan
when t = 0, v = 0
so c = 0 and v = at
s = (1/2)at^2 + k , were s is distance and k is a constant
when t = 0 , s=0 and thus k = 0
we have s = (1/2)at^2
(our physics tutors probably would have started here)
when t = 10 , s = 200
200 = (1/2)a(100)
400 = 100a
a = 4
the bus would have to accelerate at 4 m/sec^2
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