Friday

April 18, 2014

April 18, 2014

Posted by **Matt** on Monday, January 21, 2013 at 8:32am.

- Math -
**Reiny**, Monday, January 21, 2013 at 10:20amWow, a "dragster bus"

v = at + c , a is the acceleration, v is the velocity and c is a constan

when t = 0, v = 0

so c = 0 and v = at

s = (1/2)at^2 + k , were s is distance and k is a constant

when t = 0 , s=0 and thus k = 0

we have s = (1/2)at^2

(our physics tutors probably would have started here)

when t = 10 , s = 200

200 = (1/2)a(100)

400 = 100a

a = 4

the bus would have to accelerate at 4 m/sec^2

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